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(3x+3)+(11x)=(2x+1)
We move all terms to the left:
(3x+3)+(11x)-((2x+1))=0
We add all the numbers together, and all the variables
11x+(3x+3)-((2x+1))=0
We get rid of parentheses
11x+3x-((2x+1))+3=0
We calculate terms in parentheses: -((2x+1)), so:We add all the numbers together, and all the variables
(2x+1)
We get rid of parentheses
2x+1
Back to the equation:
-(2x+1)
14x-(2x+1)+3=0
We get rid of parentheses
14x-2x-1+3=0
We add all the numbers together, and all the variables
12x+2=0
We move all terms containing x to the left, all other terms to the right
12x=-2
x=-2/12
x=-1/6
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