(6w-1)/5-(3w)=(12w-16)/15

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Solution for (6w-1)/5-(3w)=(12w-16)/15 equation: 



(6w-1)/5-(3w)=(12w-16)/15

We move all terms to the left:

(6w-1)/5-(3w)-((12w-16)/15)=0

We add all the numbers together, and all the variables

-3w+(6w-1)/5-((12w-16)/15)=0

We calculate fractions


-3w+6w/()+(-((12w-16)*5)/()=0



We calculate terms in parentheses: +(-((12w-16)*5)/(), so:

-((12w-16)*5)/(

We multiply all the terms by the denominator


-((12w-16)*5)



We calculate terms in parentheses: -((12w-16)*5), so:

(12w-16)*5

We multiply parentheses

60w-80

Back to the equation:

-(60w-80)



We get rid of parentheses

-60w+80

Back to the equation:

+(-60w+80)



We get rid of parentheses

-3w+6w/()-60w+80=0

We multiply all the terms by the denominator


-3w*()+6w-60w*()+80*()=0

We add all the numbers together, and all the variables

6w-3w*()-60w*()=0

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