(6v-1)(v-1)=0

Solution for (6v-1)(v-1)=0 equation:

(6v-1)(v-1)=0

We multiply parentheses ..

(+6v^2-6v-1v+1)=0

We get rid of parentheses

6v^2-6v-1v+1=0

We add all the numbers together, and all the variables

6v^2-7v+1=0

a = 6; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·6·1
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-5}{2*6}=\frac{2}{12}
=1/6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+5}{2*6}=\frac{12}{12}
=1
$