(6v+2)*(9v+8)=0

Solution for (6v+2)*(9v+8)=0 equation:

(6v+2)(9v+8)=0

We multiply parentheses ..

(+54v^2+48v+18v+16)=0

We get rid of parentheses

54v^2+48v+18v+16=0

We add all the numbers together, and all the variables

54v^2+66v+16=0

a = 54; b = 66; c = +16;
Δ = b2-4ac
Δ = 662-4·54·16
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-30}{2*54}=\frac{-96}{108}
=-8/9
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+30}{2*54}=\frac{-36}{108}
=-1/3
$