(6v+1)(v+9)=0

Solution for (6v+1)(v+9)=0 equation:

(6v+1)(v+9)=0

We multiply parentheses ..

(+6v^2+54v+v+9)=0

We get rid of parentheses

6v^2+54v+v+9=0

We add all the numbers together, and all the variables

6v^2+55v+9=0

a = 6; b = 55; c = +9;
Δ = b2-4ac
Δ = 552-4·6·9
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-53}{2*6}=\frac{-108}{12}
=-9
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+53}{2*6}=\frac{-2}{12}
=-1/6
$