3x-(2(x+4)-3)=(4x+10)

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Solution for 3x-(2(x+4)-3)=(4x+10) equation: 



3x-(2(x+4)-3)=(4x+10)

We move all terms to the left:

3x-(2(x+4)-3)-((4x+10))=0



We calculate terms in parentheses: -(2(x+4)-3), so:

2(x+4)-3

We multiply parentheses

2x+8-3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)





We calculate terms in parentheses: -((4x+10)), so:

(4x+10)

We get rid of parentheses

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

3x-2x-4x-5-10=0

We add all the numbers together, and all the variables

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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