(6t+2/6t-7)=(2t+4/2t-3)

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Solution for (6t+2/6t-7)=(2t+4/2t-3) equation: 



(6t+2/6t-7)=(2t+4/2t-3)

We move all terms to the left:

(6t+2/6t-7)-((2t+4/2t-3))=0



Domain of the equation: 6t-7)!=0

t∈R





Domain of the equation: 2t-3))!=0

t∈R



We get rid of parentheses

6t+2/6t-((2t+4/2t-3))-7=0

We calculate fractions


6t+4t/12t^2+(-((2t+4*6t)/12t^2-7=0

We add all the numbers together, and all the variables

6t+4t/12t^2+(-((+2t+4*6t)/12t^2-7=0

We calculate fractions

We do not support etpression: t^4

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