2/3x+1/3=1/2x-4

Solution for 2/3x+1/3=1/2x-4 equation:

2/3x+1/3=1/2x-4

We move all terms to the left:

2/3x+1/3-(1/2x-4)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x-4)!=0

x∈R


We get rid of parentheses

2/3x-1/2x+4+1/3=0

We calculate fractions


4x/54x^2+(-27x)/54x^2+2x/54x^2+4=0

We multiply all the terms by the denominator


4x+(-27x)+2x+4*54x^2=0

We add all the numbers together, and all the variables

6x+(-27x)+4*54x^2=0

Wy multiply elements

216x^2+6x+(-27x)=0

We get rid of parentheses

216x^2+6x-27x=0

We add all the numbers together, and all the variables

216x^2-21x=0

a = 216; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·216·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*216}=\frac{0}{432}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*216}=\frac{42}{432}
=7/72
$