(6h-6)(h+8)=0

Solution for (6h-6)(h+8)=0 equation:

(6h-6)(h+8)=0

We multiply parentheses ..

(+6h^2+48h-6h-48)=0

We get rid of parentheses

6h^2+48h-6h-48=0

We add all the numbers together, and all the variables

6h^2+42h-48=0

a = 6; b = 42; c = -48;
Δ = b2-4ac
Δ = 422-4·6·(-48)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-54}{2*6}=\frac{-96}{12}
=-8
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+54}{2*6}=\frac{12}{12}
=1
$