x2+18x+50=9

Solution for x2+18x+50=9 equation:

x2+18x+50=9

We move all terms to the left:

x2+18x+50-(9)=0

We add all the numbers together, and all the variables

x^2+18x+41=0

a = 1; b = 18; c = +41;
Δ = b2-4ac
Δ = 182-4·1·41
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-4\sqrt{10}}{2*1}=\frac{-18-4\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+4\sqrt{10}}{2*1}=\frac{-18+4\sqrt{10}}{2}
$