(68+x)+(128+x)=180

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Solution for (68+x)+(128+x)=180 equation:



(68+x)+(128+x)=180
We move all terms to the left:
(68+x)+(128+x)-(180)=0
We add all the numbers together, and all the variables
(x+68)+(x+128)-180=0
We get rid of parentheses
x+x+68+128-180=0
We add all the numbers together, and all the variables
2x+16=0
We move all terms containing x to the left, all other terms to the right
2x=-16
x=-16/2
x=-8

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