(60-2x)=(90-22x)

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Solution for (60-2x)=(90-22x) equation: 



(60-2x)=(90-22x)

We move all terms to the left:

(60-2x)-((90-22x))=0

We add all the numbers together, and all the variables

(-2x+60)-((-22x+90))=0

We get rid of parentheses

-2x-((-22x+90))+60=0



We calculate terms in parentheses: -((-22x+90)), so:

(-22x+90)

We get rid of parentheses

-22x+90

Back to the equation:

-(-22x+90)



We get rid of parentheses

-2x+22x-90+60=0

We add all the numbers together, and all the variables

20x-30=0

We move all terms containing x to the left, all other terms to the right

20x=30

x=30/20

x=1+1/2

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