(6/x-3)+(1/x)=(6/x-3)

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Solution for (6/x-3)+(1/x)=(6/x-3) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

6/x+1/x-3 = 6/x-3 // - 6/x-3

6/x+1/x-(6/x)-3+3 = 0

6/x+1/x-6*x^-1-3+3 = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x belongs to the empty set

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