-3(4b+1)+(13b-2)=0

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Solution for -3(4b+1)+(13b-2)=0 equation:


Simplifying
-3(4b + 1) + (13b + -2) = 0

Reorder the terms:
-3(1 + 4b) + (13b + -2) = 0
(1 * -3 + 4b * -3) + (13b + -2) = 0
(-3 + -12b) + (13b + -2) = 0

Reorder the terms:
-3 + -12b + (-2 + 13b) = 0

Remove parenthesis around (-2 + 13b)
-3 + -12b + -2 + 13b = 0

Reorder the terms:
-3 + -2 + -12b + 13b = 0

Combine like terms: -3 + -2 = -5
-5 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-5 + 1b = 0

Solving
-5 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1b = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 1b = 0 + 5
1b = 0 + 5

Combine like terms: 0 + 5 = 5
1b = 5

Divide each side by '1'.
b = 5

Simplifying
b = 5

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