(6/h)-(2/(h+4))=0

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Solution for (6/h)-(2/(h+4))=0 equation: 



(6/h)-(2/(h+4))=0



Domain of the equation: h)!=0

h!=0/1

h!=0

h∈R





Domain of the equation: (h+4))!=0

h∈R



We add all the numbers together, and all the variables

(+6/h)-(2/(h+4))=0

We get rid of parentheses

6/h-(2/(h+4))=0

We calculate fractions


6h/5h^2+(-(2*h)/5h^2=0

We add all the numbers together, and all the variables

6h/5h^2+(-(+2h)/5h^2=0

We multiply all the terms by the denominator


6h+(-(+2h)=0



We calculate terms in parentheses: +(-(+2h), so:

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