(2x-2)/3=(2x+6)/7

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Solution for (2x-2)/3=(2x+6)/7 equation: 



(2x-2)/3=(2x+6)/7

We move all terms to the left:

(2x-2)/3-((2x+6)/7)=0

We calculate fractions


2x/()+(-((2x+6)*3)/()=0



We calculate terms in parentheses: +(-((2x+6)*3)/(), so:

-((2x+6)*3)/(

We multiply all the terms by the denominator


-((2x+6)*3)



We calculate terms in parentheses: -((2x+6)*3), so:

(2x+6)*3

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

-6x-18

Back to the equation:

+(-6x-18)



We get rid of parentheses

2x/()-6x-18=0

We multiply all the terms by the denominator


2x-6x*()-18*()=0

We add all the numbers together, and all the variables

2x-6x*()=0

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