(6/7)+(7m/3)=(74/31)

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Solution for (6/7)+(7m/3)=(74/31) equation: 



(6/7)+(7m/3)=(74/31)

We move all terms to the left:

(6/7)+(7m/3)-((74/31))=0

We add all the numbers together, and all the variables

(+7m/3)+(+6/7)-((+74/31))=0

We get rid of parentheses

7m/3+6/7-((+74/31))=0

We calculate fractions


4557m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

4557m^2/()+2=0

We multiply all the terms by the denominator


4557m^2+2*()=0

We add all the numbers together, and all the variables

4557m^2=0

a = 4557; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4557·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{9114}=0$

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