3(2x-4)+12=6x-4+4

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Solution for 3(2x-4)+12=6x-4+4 equation: 



3(2x-4)+12=6x-4+4

We move all terms to the left:

3(2x-4)+12-(6x-4+4)=0

We add all the numbers together, and all the variables

3(2x-4)-(+6x)+12=0

We multiply parentheses

6x-(+6x)-12+12=0

We get rid of parentheses

6x-6x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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