(6/3u-18)-3=2/u-6

Solution for (6/3u-18)-3=2/u-6 equation:

(6/3u-18)-3=2/u-6

We move all terms to the left:

(6/3u-18)-3-(2/u-6)=0


Domain of the equation: 3u-18)!=0

u∈R



Domain of the equation: u-6)!=0

u∈R


We get rid of parentheses

6/3u-2/u-18+6-3=0

We calculate fractions


6u/3u^2+(-6u)/3u^2-18+6-3=0

We add all the numbers together, and all the variables

6u/3u^2+(-6u)/3u^2-15=0

We multiply all the terms by the denominator


6u+(-6u)-15*3u^2=0

Wy multiply elements

-45u^2+6u+(-6u)=0

We get rid of parentheses

-45u^2+6u-6u=0

We add all the numbers together, and all the variables

-45u^2=0

a = -45; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-45)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{0}{-90}=0$