(6-3x)+2=5-(2x-1)

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Solution for (6-3x)+2=5-(2x-1) equation: 



(6-3x)+2=5-(2x-1)

We move all terms to the left:

(6-3x)+2-(5-(2x-1))=0

We add all the numbers together, and all the variables

(-3x+6)-(5-(2x-1))+2=0

We get rid of parentheses

-3x-(5-(2x-1))+6+2=0



We calculate terms in parentheses: -(5-(2x-1)), so:

5-(2x-1)

determiningTheFunctionDomain
-(2x-1)+5

We get rid of parentheses

-2x+1+5

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

-3x-(-2x+6)+8=0

We get rid of parentheses

-3x+2x-6+8=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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