(6*(1/3))*(4a+1)=(6*(1/2))*a

Solution for (6*(1/3))*(4a+1)=(6*(1/2))*a equation:

(6(1/3))(4a+1)=(6(1/2))*a

We move all terms to the left:

(6(1/3))(4a+1)-((6(1/2))*a)=0


Domain of the equation: 3))(4a+1)!=0

a∈R



Domain of the equation: 2))*a)!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

(6(+1/3))(4a+1)-((6(+1/2))*a)=0

We calculate fractions


62a/3)(4a+1)*2))*a))+(-(63(4a+1))/3)(4a+1)*2))*a))=0

We calculate fractions


(186a^2+1)*2))*a)))/(12a^2+1)*2))*a))+3)()+1*2))*a))+(-(63(4a+1))*3)4a/(12a^2+1)*2))*a))+3)()=0

We can not solve this equation