S=5(2z-5)

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Solution for S=5(2z-5) equation: 



=5(2S-5)

We move all terms to the left:

-(5(2S-5))=0



We calculate terms in parentheses: -(5(2S-5)), so:

5(2S-5)

We multiply parentheses

10S-25

Back to the equation:

-(10S-25)



We get rid of parentheses

-10S+25=0

We move all terms containing S to the left, all other terms to the right

-10S=-25

S=-25/-10

S=2+1/2

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