(5y-8)=(3y)/5+4y+6

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Solution for (5y-8)=(3y)/5+4y+6 equation: 



(5y-8)=(3y)/5+4y+6

We move all terms to the left:

(5y-8)-((3y)/5+4y+6)=0



Domain of the equation: 5+4y+6)!=0

We move all terms containing y to the left, all other terms to the right

4y+6)!=-5

y∈R



We add all the numbers together, and all the variables

(5y-8)-(4y+3y/5+6)=0

We get rid of parentheses

5y-4y-3y/5-8-6=0

We multiply all the terms by the denominator


5y*5-4y*5-3y-8*5-6*5=0

We add all the numbers together, and all the variables

-3y+5y*5-4y*5-70=0

Wy multiply elements

-3y+25y-20y-70=0

We add all the numbers together, and all the variables

2y-70=0

We move all terms containing y to the left, all other terms to the right

2y=70

y=70/2

y=35

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