-2(2-4x)-(1-x)=4(x-2)

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Solution for -2(2-4x)-(1-x)=4(x-2) equation:



-2(2-4x)-(1-x)=4(x-2)
We move all terms to the left:
-2(2-4x)-(1-x)-(4(x-2))=0
We add all the numbers together, and all the variables
-2(-4x+2)-(-1x+1)-(4(x-2))=0
We multiply parentheses
8x-(-1x+1)-(4(x-2))-4=0
We get rid of parentheses
8x+1x-(4(x-2))-1-4=0
We calculate terms in parentheses: -(4(x-2)), so:
4(x-2)
We multiply parentheses
4x-8
Back to the equation:
-(4x-8)
We add all the numbers together, and all the variables
9x-(4x-8)-5=0
We get rid of parentheses
9x-4x+8-5=0
We add all the numbers together, and all the variables
5x+3=0
We move all terms containing x to the left, all other terms to the right
5x=-3
x=-3/5
x=-3/5

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