(5y-7)=(3y-1)

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Solution for (5y-7)=(3y-1) equation: 



(5y-7)=(3y-1)

We move all terms to the left:

(5y-7)-((3y-1))=0

We get rid of parentheses

5y-((3y-1))-7=0



We calculate terms in parentheses: -((3y-1)), so:

(3y-1)

We get rid of parentheses

3y-1

Back to the equation:

-(3y-1)



We get rid of parentheses

5y-3y+1-7=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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