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(2x+3)(x+4)=180
We move all terms to the left:
(2x+3)(x+4)-(180)=0
We multiply parentheses ..
(+2x^2+8x+3x+12)-180=0
We get rid of parentheses
2x^2+8x+3x+12-180=0
We add all the numbers together, and all the variables
2x^2+11x-168=0
a = 2; b = 11; c = -168;
Δ = b2-4ac
Δ = 112-4·2·(-168)
Δ = 1465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{1465}}{2*2}=\frac{-11-\sqrt{1465}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{1465}}{2*2}=\frac{-11+\sqrt{1465}}{4} $
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