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(5y-50)=(4y-10)
We move all terms to the left:
(5y-50)-((4y-10))=0
We get rid of parentheses
5y-((4y-10))-50=0
We calculate terms in parentheses: -((4y-10)), so:We get rid of parentheses
(4y-10)
We get rid of parentheses
4y-10
Back to the equation:
-(4y-10)
5y-4y+10-50=0
We add all the numbers together, and all the variables
y-40=0
We move all terms containing y to the left, all other terms to the right
y=40
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