8-2(x+1)=7(x-3)

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Solution for 8-2(x+1)=7(x-3) equation: 



8-2(x+1)=7(x-3)

We move all terms to the left:

8-2(x+1)-(7(x-3))=0

We multiply parentheses

-2x-(7(x-3))-2+8=0



We calculate terms in parentheses: -(7(x-3)), so:

7(x-3)

We multiply parentheses

7x-21

Back to the equation:

-(7x-21)



We add all the numbers together, and all the variables

-2x-(7x-21)+6=0

We get rid of parentheses

-2x-7x+21+6=0

We add all the numbers together, and all the variables

-9x+27=0

We move all terms containing x to the left, all other terms to the right

-9x=-27

x=-27/-9

x=+3

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