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(5x-8)(5x+2)=0
We multiply parentheses ..
(+25x^2+10x-40x-16)=0
We get rid of parentheses
25x^2+10x-40x-16=0
We add all the numbers together, and all the variables
25x^2-30x-16=0
a = 25; b = -30; c = -16;
Δ = b2-4ac
Δ = -302-4·25·(-16)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-50}{2*25}=\frac{-20}{50} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+50}{2*25}=\frac{80}{50} =1+3/5 $
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