2x-3(2-3x)=3(x-3)-45

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Solution for 2x-3(2-3x)=3(x-3)-45 equation: 



2x-3(2-3x)=3(x-3)-45

We move all terms to the left:

2x-3(2-3x)-(3(x-3)-45)=0

We add all the numbers together, and all the variables

2x-3(-3x+2)-(3(x-3)-45)=0

We multiply parentheses

2x+9x-(3(x-3)-45)-6=0



We calculate terms in parentheses: -(3(x-3)-45), so:

3(x-3)-45

We multiply parentheses

3x-9-45

We add all the numbers together, and all the variables

3x-54

Back to the equation:

-(3x-54)



We add all the numbers together, and all the variables

11x-(3x-54)-6=0

We get rid of parentheses

11x-3x+54-6=0

We add all the numbers together, and all the variables

8x+48=0

We move all terms containing x to the left, all other terms to the right

8x=-48

x=-48/8

x=-6

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