(5x-6)/3=(2x+9)/9

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Solution for (5x-6)/3=(2x+9)/9 equation: 



(5x-6)/3=(2x+9)/9

We move all terms to the left:

(5x-6)/3-((2x+9)/9)=0

We calculate fractions


5x/()+(-((2x+9)*3)/()=0



We calculate terms in parentheses: +(-((2x+9)*3)/(), so:

-((2x+9)*3)/(

We multiply all the terms by the denominator


-((2x+9)*3)



We calculate terms in parentheses: -((2x+9)*3), so:

(2x+9)*3

We multiply parentheses

6x+27

Back to the equation:

-(6x+27)



We get rid of parentheses

-6x-27

Back to the equation:

+(-6x-27)



We get rid of parentheses

5x/()-6x-27=0

We multiply all the terms by the denominator


5x-6x*()-27*()=0

We add all the numbers together, and all the variables

5x-6x*()=0

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