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(5x-6)(3x+16)+(x+8)=180
We move all terms to the left:
(5x-6)(3x+16)+(x+8)-(180)=0
We get rid of parentheses
(5x-6)(3x+16)+x+8-180=0
We multiply parentheses ..
(+15x^2+80x-18x-96)+x+8-180=0
We add all the numbers together, and all the variables
(+15x^2+80x-18x-96)+x-172=0
We get rid of parentheses
15x^2+80x-18x+x-96-172=0
We add all the numbers together, and all the variables
15x^2+63x-268=0
a = 15; b = 63; c = -268;
Δ = b2-4ac
Δ = 632-4·15·(-268)
Δ = 20049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{20049}}{2*15}=\frac{-63-\sqrt{20049}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{20049}}{2*15}=\frac{-63+\sqrt{20049}}{30} $
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