3(4i-1)=10i+25

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Solution for 3(4i-1)=10i+25 equation: 



3(4i-1)=10i+25

We move all terms to the left:

3(4i-1)-(10i+25)=0

We multiply parentheses

12i-(10i+25)-3=0

We get rid of parentheses

12i-10i-25-3=0

We add all the numbers together, and all the variables

2i-28=0

We move all terms containing i to the left, all other terms to the right

2i=28

i=28/2

i=14

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