(5x-4)/4=(4x-5)/3

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Solution for (5x-4)/4=(4x-5)/3 equation: 



(5x-4)/4=(4x-5)/3

We move all terms to the left:

(5x-4)/4-((4x-5)/3)=0

We calculate fractions


5x/()+(-((4x-5)*4)/()=0



We calculate terms in parentheses: +(-((4x-5)*4)/(), so:

-((4x-5)*4)/(

We multiply all the terms by the denominator


-((4x-5)*4)



We calculate terms in parentheses: -((4x-5)*4), so:

(4x-5)*4

We multiply parentheses

16x-20

Back to the equation:

-(16x-20)



We get rid of parentheses

-16x+20

Back to the equation:

+(-16x+20)



We get rid of parentheses

5x/()-16x+20=0

We multiply all the terms by the denominator


5x-16x*()+20*()=0

We add all the numbers together, and all the variables

5x-16x*()=0

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