5x(25x-5)=1900

Solution for 5x(25x-5)=1900 equation:

5x(25x-5)=1900

We move all terms to the left:

5x(25x-5)-(1900)=0

We multiply parentheses

125x^2-25x-1900=0

a = 125; b = -25; c = -1900;
Δ = b2-4ac
Δ = -252-4·125·(-1900)
Δ = 950625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{950625}=975$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-975}{2*125}=\frac{-950}{250}
=-3+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+975}{2*125}=\frac{1000}{250}
=4
$