(5x-4)(2x)=(x)(3x+6)

Solution for (5x-4)(2x)=(x)(3x+6) equation:

(5x-4)(2x)=(x)(3x+6)

We move all terms to the left:

(5x-4)(2x)-((x)(3x+6))=0

We multiply parentheses

10x^2-8x-(x(3x+6))=0


We calculate terms in parentheses: -(x(3x+6)), so:

x(3x+6)

We multiply parentheses

3x^2+6x

Back to the equation:

-(3x^2+6x)


We get rid of parentheses

10x^2-3x^2-8x-6x=0

We add all the numbers together, and all the variables

7x^2-14x=0

a = 7; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·7·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*7}=\frac{0}{14}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*7}=\frac{28}{14}
=2
$