3(y-1)=2(y+3)+13

Solution for 3(y-1)=2(y+3)+13 equation:

3(y-1)=2(y+3)+13

We move all terms to the left:

3(y-1)-(2(y+3)+13)=0

We multiply parentheses

3y-(2(y+3)+13)-3=0


We calculate terms in parentheses: -(2(y+3)+13), so:

2(y+3)+13

We multiply parentheses

2y+6+13

We add all the numbers together, and all the variables

2y+19

Back to the equation:

-(2y+19)


We get rid of parentheses

3y-2y-19-3=0

We add all the numbers together, and all the variables

y-22=0

We move all terms containing y to the left, all other terms to the right

y=22