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(5x-3)(5x+11)=0
We multiply parentheses ..
(+25x^2+55x-15x-33)=0
We get rid of parentheses
25x^2+55x-15x-33=0
We add all the numbers together, and all the variables
25x^2+40x-33=0
a = 25; b = 40; c = -33;
Δ = b2-4ac
Δ = 402-4·25·(-33)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-70}{2*25}=\frac{-110}{50} =-2+1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+70}{2*25}=\frac{30}{50} =3/5 $
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