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3(x+2)=5(10-2x)
We move all terms to the left:
3(x+2)-(5(10-2x))=0
We add all the numbers together, and all the variables
3(x+2)-(5(-2x+10))=0
We multiply parentheses
3x-(5(-2x+10))+6=0
We calculate terms in parentheses: -(5(-2x+10)), so:We get rid of parentheses
5(-2x+10)
We multiply parentheses
-10x+50
Back to the equation:
-(-10x+50)
3x+10x-50+6=0
We add all the numbers together, and all the variables
13x-44=0
We move all terms containing x to the left, all other terms to the right
13x=44
x=44/13
x=3+5/13
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