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(5x-2)(5x-2)/4x=0
Domain of the equation: 4x!=0We multiply parentheses ..
x!=0/4
x!=0
x∈R
(+25x^2-10x-10x+4)/4x=0
We multiply all the terms by the denominator
(+25x^2-10x-10x+4)=0
We get rid of parentheses
25x^2-10x-10x+4=0
We add all the numbers together, and all the variables
25x^2-20x+4=0
a = 25; b = -20; c = +4;
Δ = b2-4ac
Δ = -202-4·25·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{20}{50}=2/5$
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