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(5x-19)(2x+5)=119
We move all terms to the left:
(5x-19)(2x+5)-(119)=0
We multiply parentheses ..
(+10x^2+25x-38x-95)-119=0
We get rid of parentheses
10x^2+25x-38x-95-119=0
We add all the numbers together, and all the variables
10x^2-13x-214=0
a = 10; b = -13; c = -214;
Δ = b2-4ac
Δ = -132-4·10·(-214)
Δ = 8729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{8729}}{2*10}=\frac{13-\sqrt{8729}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{8729}}{2*10}=\frac{13+\sqrt{8729}}{20} $
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