2(x-3)+4x-5=3-2(x+1)

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Solution for 2(x-3)+4x-5=3-2(x+1) equation: 



2(x-3)+4x-5=3-2(x+1)

We move all terms to the left:

2(x-3)+4x-5-(3-2(x+1))=0

We add all the numbers together, and all the variables

4x+2(x-3)-(3-2(x+1))-5=0

We multiply parentheses

4x+2x-(3-2(x+1))-6-5=0



We calculate terms in parentheses: -(3-2(x+1)), so:

3-2(x+1)

determiningTheFunctionDomain
-2(x+1)+3

We multiply parentheses

-2x-2+3

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We add all the numbers together, and all the variables

6x-(-2x+1)-11=0

We get rid of parentheses

6x+2x-1-11=0

We add all the numbers together, and all the variables

8x-12=0

We move all terms containing x to the left, all other terms to the right

8x=12

x=12/8

x=1+1/2

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