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(5x-12)=(3x)
We move all terms to the left:
(5x-12)-((3x))=0
determiningTheFunctionDomain (5x-12)-3x=0
We add all the numbers together, and all the variables
-3x+(5x-12)=0
We get rid of parentheses
-3x+5x-12=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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