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3(c+4)=(c+5)
We move all terms to the left:
3(c+4)-((c+5))=0
We multiply parentheses
3c-((c+5))+12=0
We calculate terms in parentheses: -((c+5)), so:We get rid of parentheses
(c+5)
We get rid of parentheses
c+5
Back to the equation:
-(c+5)
3c-c-5+12=0
We add all the numbers together, and all the variables
2c+7=0
We move all terms containing c to the left, all other terms to the right
2c=-7
c=-7/2
c=-3+1/2
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