(5x-10)+(x+45)+(65-2x)=180

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Solution for (5x-10)+(x+45)+(65-2x)=180 equation: 



(5x-10)+(x+45)+(65-2x)=180

We move all terms to the left:

(5x-10)+(x+45)+(65-2x)-(180)=0

We add all the numbers together, and all the variables

(5x-10)+(x+45)+(-2x+65)-180=0

We get rid of parentheses

5x+x-2x-10+45+65-180=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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