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(4x-5)/(2x+3)=0
Domain of the equation: (2x+3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=-3
x!=-3/2
x!=-1+1/2
x∈R
(4x-5)=0
We get rid of parentheses
4x-5=0
We move all terms containing x to the left, all other terms to the right
4x=5
x=5/4
x=1+1/4
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