3(2f-5)=3(f+3)

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Solution for 3(2f-5)=3(f+3) equation: 



3(2f-5)=3(f+3)

We move all terms to the left:

3(2f-5)-(3(f+3))=0

We multiply parentheses

6f-(3(f+3))-15=0



We calculate terms in parentheses: -(3(f+3)), so:

3(f+3)

We multiply parentheses

3f+9

Back to the equation:

-(3f+9)



We get rid of parentheses

6f-3f-9-15=0

We add all the numbers together, and all the variables

3f-24=0

We move all terms containing f to the left, all other terms to the right

3f=24

f=24/3

f=8

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