(5x-1)(x+3)-(x+5)(5x+1)=40

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Solution for (5x-1)(x+3)-(x+5)(5x+1)=40 equation:



(5x-1)(x+3)-(x+5)(5x+1)=40
We move all terms to the left:
(5x-1)(x+3)-(x+5)(5x+1)-(40)=0
We multiply parentheses ..
(+5x^2+15x-1x-3)-(x+5)(5x+1)-40=0
We get rid of parentheses
5x^2+15x-1x-(x+5)(5x+1)-3-40=0
We multiply parentheses ..
5x^2-(+5x^2+x+25x+5)+15x-1x-3-40=0
We add all the numbers together, and all the variables
5x^2-(+5x^2+x+25x+5)+14x-43=0
We get rid of parentheses
5x^2-5x^2-x-25x+14x-5-43=0
We add all the numbers together, and all the variables
-12x-48=0
We move all terms containing x to the left, all other terms to the right
-12x=48
x=48/-12
x=-4

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