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(5x+7)(3x-9)=0
We multiply parentheses ..
(+15x^2-45x+21x-63)=0
We get rid of parentheses
15x^2-45x+21x-63=0
We add all the numbers together, and all the variables
15x^2-24x-63=0
a = 15; b = -24; c = -63;
Δ = b2-4ac
Δ = -242-4·15·(-63)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-66}{2*15}=\frac{-42}{30} =-1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+66}{2*15}=\frac{90}{30} =3 $
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