8(2x-3)-2=2-(3x-2)

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Solution for 8(2x-3)-2=2-(3x-2) equation: 



8(2x-3)-2=2-(3x-2)

We move all terms to the left:

8(2x-3)-2-(2-(3x-2))=0

We multiply parentheses

16x-(2-(3x-2))-24-2=0



We calculate terms in parentheses: -(2-(3x-2)), so:

2-(3x-2)

determiningTheFunctionDomain
-(3x-2)+2

We get rid of parentheses

-3x+2+2

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We add all the numbers together, and all the variables

16x-(-3x+4)-26=0

We get rid of parentheses

16x+3x-4-26=0

We add all the numbers together, and all the variables

19x-30=0

We move all terms containing x to the left, all other terms to the right

19x=30

x=30/19

x=1+11/19

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